Implement atoi

Question

Implement atoi

S.A. · Accepted Answer

int myatoi(char *string) {
    int val = 0;

    if (string) {  // Error checking to eliminate NULL string
        while (*string && *string = '0') {
            val = (val * 10) + (*string - '0');
            string++;
            if (*string != '\0' && !(*string = '0'))
                return 0; // Error checking to eliminate cases like '12ABC34'
        }
    }
    return val;
}

AV · Answer

atoi also handles the case when there is a leading plus or minus in the string. Also it doesnt go to the end of the string. Just till the first white space character in the string

simple_coder · Answer

int my_atoi(char *str)
{
	int ret = 0,sign=1;
	if(*str == '-')
	{  
	  sign = -1;
	  str++;
	}
	while(*str)
	{
		ret = (ret * 10) + (*str - '0');
		str++;
	}
	return ret*sign;
}

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